Introduction:
n in java
Here’s a Java program to calculate the sum of n in java
what is n in java
1 + 1/2 + 1/3 + 1/4 + ... + 1/n
: import java.util.Scanner;
public class SeriesSum {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter the value of n: ");
int n = input.nextInt();
double sum = 0;
for (int i = 1; i <= n; i++) {
sum += 1.0 / i;
}
System.out.println("The sum of the series is: " + sum);
}
}n in java
In this program we first use the value of n in java as input the user which is using the scanner class. After that we declare a variable sum to store of the series and initialize it to 0
Then we use loop for iterate of 1/ I to ensure that the division is done using double precision.
After all we print the sum of the series using System.out.println().
For using these program, we can compile it a java compiler such a java and the run it using the java virtual machine {jvm}
Java series sum
When the program is run , it will prompt you to enter the value of n . we can enter any positive integer value of n the program will calculate the sum of series by using formula motioned in the above article
For example when you enter 5 as the value of n the program will output :
Enter the value of n:5
The sum of the series in n in java is : 2.283333333333333
Which means that the sum of the series : 1 + 1/2 + 1/3 + 1/4 + 1/5 is approximately equal to 2.283333333333333.
This how we can find n in java
