Write C# program to count even and odd elements in an array

Introduction

I have used Visual Studio 2012 for debugging purpose. But you can use any version of visul studio as per your availability.

using System;
class Program
{
    static void Main()
    {       
        int[] arr = new int[100];
        int i, num, evennum, oddnum;
 
        ////Reads size and elements in array
        Console.WriteLine("Enter size of the array: ");
        num = Convert.ToInt32(Console.ReadLine());
        Console.WriteLine("Enter "+num+" elements in the array: ");  
 
        for(i=0; i<num; i++)
        {
            arr[i] = Convert.ToInt32(Console.ReadLine());            
        }
 
        evennum = 0; // Assuming 0 even numbers
        oddnum = 0; // Assuming 0 odd numbers
 
        for (i = 0; i < num; i++)
        {
            /* If the current element of array is evennumber then increment evennumber count */
            if (arr[i] % 2 == 0)
            {
                evennum++;
            }
            else
            {
                oddnum++; // increment oddnumber count
            }
        }
 
        Console.WriteLine("Total even  numbers: "+evennum);
        Console.WriteLine("Total odd numbers: " + oddnum);
 
 
        Console.ReadLine();
    }
 
}

Result

Write C# program to count even and odd elements in an array
Write C# program to count even and odd elements in an array

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